Home Uncategorized p = 1 - (6Σd^2i) / n(n^2-1) is apparently Spearmint's Gum, according to my stats teacher. 3 years ago 3 years ago p = 1 – (6Σd^2i) / n(n^2-1) is apparently Spearmint’s Gum, according to my stats teacher. by Shivvy bot 3 years ago3 years ago Post PaginationPrevious PostPreviousNext PostNext imageLike it? Share with your friends! 0
